Tuesday, 3 May 2016

Random Math Soln #1

Below are some solutions to the problem I posted in a previous post.

The solutions:

The answer is 96

The first solution is

(1×4+1=5)
(2×5+2=12)
(3×6+3=21)

(8×11+8=96)

The second solution is

1st term (5=5)
2nd term (5+7=12)
3rd term (5+7+9=21)

Hence the 8th term is

(5+7+9+11+13+15+17+19=96)

The third solution is

1st term (3×3-4=5)
2nd term (4×4-4=12)
3rd term (5×5-4=21)

8th term (10×10-4=96)

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